Base converter. Lattice Multiplication. Jain's True Value of Pi. I will be releasing a new body of work that gives the True Value of Pi, based on the Harmonics of Phi (1.618033...), a value close to 3.144...
The ancient Mathematics masters have always known that the two most important transcendental numbers Pi and Phi are intimately related. As shown on this website, The Book of Phi, volumes 1 and 2 are available, but the upcoming, unpublished volumes of 3 and 4 will reveal this Pi Phi Connection and how 3.144... is derived from the Square Root of Phi (1.272...).
These two books, THE BOOK OF PHI volumes 3 and 4 are based on the 24 Repeating Pattern of the Digitally Compressed Fibonacci Sequence that encodes the frequency of 108, that anointed Vedic Number sonically encrypted in the prayers for enlightenment known as the GAYATRI MANTRA. Visualize a Hexagon in the Circle which has 6 straight lined chords. Name a Theorem. By placing an order with TheoryMine, you name a newly discovered mathematical theorem¹.
This lets you immortalise your loved ones, teachers, friends and even yourself and your favourite pets! Mathematical immortality? Name that theorem - physics-math - 03 December 2010. During my time as an eager undergraduate mathematician, I'd often wonder what it would feel like to prove a truly new result and have my name immortalised in the mathematical history books.
I thought that dream had died when I gave up maths to become a science writer, but Aron's theorem is now a reality – and I've got the certificate to prove it. 2011 preview: Million-dollar mathematics problem - physics-math - 27 December 2010. Read more: "In with the New Scientist: Our predictions for 2011" A draft solution to the so-called "P versus NP" problem generated excitement in 2010 – will 2011 bring a correct proof?
Vinay Deolalikar made waves in August when his draft solution to a mathematical problem that haunts computer science hit the internet. It's known as "P versus NP", and a correct solution is worth $1 million. Sadly for Deolalikar, of Hewlett-Packard Labs in Palo Alto, California, his work didn't check out. Make way for mathematical matter - physics-math - 05 January 2011. Editorial: "The deep value of mathematics" WE ALREADY have solid, liquid, gas, plasma and Bose-Einstein condensate.
Now it seems we may be on the verge of discovering a whole host of new forms of matter - all based on mathematics. Nils Baas, a mathematician at the Norwegian University of Science and Technology in Trondheim, has unearthed a plethora of possibilities for the way the components of matter can link together. Π really is wrong! I've written recently about several different crackpots who insist, for a variety of completely ridiculous reasons, that is wrong.
But the other day, someone sent me a link to a completely serious site that makes a pretty compelling argument that really is wrong. Happy Tau Day? « Math Goes Pop! In the past, I’ve used this blog as a platform to make clear my mixed feelings about Pi Day, a math themed holiday celebrated every year on March 14th (3/14, har har) in honor of the beloved mathematical constant .
My thoughts on the subject can be found here. It would seem that I am not alone in my frustration. Why we have to get rid of pi for the sake of good math. Ancient puzzle gets new lease of 'geomagical' life - physics-math - 24 January 2011. An ancient mathematical puzzle that has fascinated mathematicians for centuries has found a new lease of life.
The magic square is the basis for Sudoku, pops up in Chinese legend and provides a playful way to introduce children to arithmetic. But all this time it has been concealing a more complex geometrical form, says recreational mathematician Lee Sallows. He has dubbed the new kind of structure the "geomagic square", and recently released dozens of examples online. Click here to see a gallery of geomagic squares. Deep meaning in Ramanujan's 'simple' pattern - physics-math - 27 January 2011. The first simple formula has been found for calculating how many ways a number can be created by adding together other numbers, solving a puzzle that captivated the legendary mathematician Srinivasa Ramanujan.
Someone told me that if there are 20 people in a room, there's a 50/50 chance that two of them will have the same birthday. How can that be?" This phenomenon actually has a name -- it is called the birthday paradox, and it turns out it is useful in several different areas (for example, cryptography and hashing algorithms).
You can try it yourself -- the next time you are at a gathering of 20 or 30 people, ask everyone for their birth date. It is likely that two people in the group will have the same birthday. It always surprises people! The reason this is so surprising is because we are used to comparing our particular birthdays with others. For example, if you meet someone randomly and ask him what his birthday is, the chance of the two of you having the same birthday is only 1/365 (0.27%). When you put 20 people in a room, however, the thing that changes is the fact that each of the 20 people is now asking each of the other 19 people about their birthdays.
If you want to calculate the exact probability, one way to look at it is like this. Why-couldnt-i-have-been-shown-this-in-maths-class.gif (GIF Image, 251x231 pixels) Stephen Wolfram: Computing a theory of everything.
Nerd Paradise : Divisibility Rules for Arbitrary Divisors. It's rather obvious when a number is divisible by 2 or 5, and some of you probably know how to tell if a number is divisible by 3, but it is possible to figure out the division 'rule' for any number. Here are the rules for 2 through 11... The last digit is divisible by 2. The sum of all the digits in the number is divisible by 3. The last 2 digits are divisible by 4. Arthur Benjamin does "Mathemagic" Folding Paper in Half Twelve Times.
Folding Paper in Half 12 Times: The story of an impossible challenge solved at the Historical Society office Alice laughed: "There's no use trying," she said; "one can't believe impossible things. " "I daresay you haven't had much practice," said the Queen. Through the Looking Glass by L. Carroll The long standing challenge was that a single piece of paper, no matter the size, cannot be folded in half more than 7 or 8 times. The most significant part of Britney's work is actually not the geometric progression of a folding sequence but rather the detailed analysis to find why geometric sequences have practical limits that prevent them from expanding. Her book provides the size of paper needed to fold paper and gold 16 times using different folding techniques.
Britney Gallivan has solved the Paper Folding Problem. In April of 2005 Britney's accomplishment was mentioned on the prime time CBS television show Numb3rs. Hypotrochoid_R_equals_7,_r_equals_2,_d=3.gif (GIF Image, 400x400 pixels) Bill the Lizard: Six Visual Proofs. 1 + 2 + 3 + ... + n = n * (n+1) / 2 1 + 3 + 5 + ... + (2n − 1) = n2 Related posts:Math visualization: (x + 1)2 Further reading:Proof without Words: Exercises in Visual ThinkingQ.E.D.: Beauty in Mathematical Proof. Mathematica Online Integrator. Calculus Mega Cheat Sheet. What does 0^0 (zero raised to the zeroth power) equal? Why do mathematicians and high school teachers disagree. Clever student: I know! Now we just plug in x=0, and we see that zero to the zero is one! Cleverer student: No, you’re wrong!
You’re not allowed to divide by zero, which you did in the last step. Which is true since anything times 0 is 0. Weierstrass functions. Weierstrass functions are famous for being continuous everywhere, but differentiable "nowhere". Here is an example of one: It is not hard to show that this series converges for all x. In fact, it is absolutely convergent. Web Design and Development. The On-Line Encyclopedia of Integer Sequences™ (OEIS™)
Approximating Pi (non-Flash) Solve Your Calculus Problems Online. PatrickJMT. 6174 (number) 6174 is known as Kaprekar's constant after the Indian mathematician D. R. Kaprekar. This number is notable for the following property: Take any four-digit number, using at least two different digits. (Leading zeros are allowed.)Arrange the digits in ascending and then in descending order to get two four-digit numbers, adding leading zeros if necessary.Subtract the smaller number from the bigger number.Go back to step 2. 9990 – 0999 = 8991 (rather than 999 – 999 = 0) 9831 reaches 6174 after 7 iterations: 8820 – 0288 = 8532 (rather than 882 – 288 = 594) 8774, 8477, 8747, 7748, 7487, 7847, 7784, 4877, 4787, and 4778 reach 6174 after 4 iterations: Note that in each iteration of Kaprekar's routine, the two numbers being subtracted one from the other have the same digit sum and hence the same remainder modulo 9.
Mathematicians Solve 140-Year-Old Boltzmann Equation. Unsolved Problems. Wolfram MathWorld: The Web's Most Extensive Mathematics Resource.